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11-26-2008   #1 (permalink)
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Default Highschool Physics problem

A 1.8kg object is pulled along the floor w/ a force if 7.0N acting horizontally. If the object accelerates at 2.4m/s^2, how much kinetic friction is acting?

i assumed it' looking for coefficient of friction but the answers are all in N

Answers are a. 26N b. 11N c. 10N d. 6.4N e. 4.9N

Here's what i'm thinking. i have 2 formulas
Ffriction = coefficient of friction x Fnet and
Fnet = ma

m = 1.8, a = 2.4 from question. So Fnet = 4.32N. I assumed then, the 7N in question is the friction force, but then...i would be finding what the coefficient of friction is..and i got 1.6 (what's the unit for it?) which doesn't match...and i dont' think it's in N.

I don't even know what the question is asking for, help please?
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11-27-2008   #2 (permalink)
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I think Fnet is mu (which is the constant of the friction) x ma. If you plug in the known variables, you can isolate mu which is the constant of the friction.

I'm doing this same stuff right now myself and I'm having trouble with it, too. Tell me if that's wrong or not DX
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11-28-2008   #3 (permalink)
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Ff is found by normal force x the coefficient of friction...
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11-28-2008   #4 (permalink)
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Fnet = mass X acceleration
Ffric = coefficient of kinetic friction X Fnormal

In this question if it`s asking only for Kinetic Friction so the answer should be just 2.68 N if that were one of the numbers.

If you were to find the coefficient, you`d use the value for Ffric divided by Fnormal.

2.68/(1.8 * 9.8)

= 0.15 no units.
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