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08-26-2012   #1 (permalink)
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Default Chemistry Help
The ratio of A to B by mass in A2B3 is 0.4297. The ratio of A to C by mass in AC is 5.712. Find the ratio of B to C by mass in B2C.


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08-26-2012   #2 (permalink)
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I suck at this. So, I will help.

a/c =5.712

c=5.712a

2c/3b=(.4297/5.712)

3b/2c = (5.712/.4297)

2b/c = (4/3) * (5.712/.4297)

ratio = 17.72?

If I'm wrong, Cepheid will be our savior.
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08-26-2012   #3 (permalink)
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Originally Posted by iFarted
I suck at this. So, I will help.

a/c =5.712

c=5.712a

2c/3b=(.4297/5.712)

3b/2c = (5.712/.4297)

2b/c = (4/3) * (5.712/.4297)

ratio = 17.72?

If I'm wrong, Cepheid will be our savior.
how did ur c=5.712a suddenly become 2c/3b?
 
08-26-2012   #4 (permalink)
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I substituted c into 2a/3b = .4297
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08-26-2012   #5 (permalink)
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ah i see, thx for ur help
 
08-27-2012   #6 (permalink)
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Quote:
Originally Posted by iFarted
I suck at this. So, I will help.

a/c =5.712

c=5.712a

2c/3b=(.4297/5.712)

3b/2c = (5.712/.4297)

2b/c = (4/3) * (5.712/.4297)

ratio = 17.72?

If I'm wrong, Cepheid will be our savior.
Looks fine to me
And savior? I doubt it, there was no need for me.
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