Amg thanks for your fast reply! And thanks, I also kind of understood what to do :
so I did this like you said:
f(2) = 0
8a+4b3(2)+2 = 0
0=8a+4b4
f(1)=0
a+b3+2=0
a+b1 = 0  +1
a+b = 1 +a
b= 1+a
Now I substitued b into 0=8a+4b4 which will be:
8a+4(1+a)4
0=8a+4+4a4
0=12a:12
a=0
Substitued a into 1+a:
b=1+0 =1
The equation is:
f(x)=x²+3x+2
Is this right? Because it's only 2. Degree polynomial
thanks in advance!
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